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JuliaJuliaJulia
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Group: Forum Members
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+x+x+x[quote]If you want the width to be fixed, but the height to vary, that works in the same way. Ah, so I will create another list element, so that I have in sum two list elements: on for the width and one for the height. I just have problems to understand this pice of code: <picture mypicture>/ items = myitems/ height = 80%/ width = 0%/ position = (50%, 50%)</picture><list widths>/ items = (80%, 40%)/ selectionmode = picture.mypicture.nextindex</list>
For the first item ("01.jpg"; so the horizontal image) the height is set to 80% and the width also to 80%. But that shouldn't be so: The width should be set to 80% and the hight should be allowed to vary... For the second item ("02.jpg"; so the horizontal image) the height is set to 80% and the width to 40%. That also shouldn't be so: The hight should be set to 80% and the width should be allowed to vary and shouldn't be fixed to 40%... Is there a possibility to do that? Best Julia Just flip what I illustrated for the width in the example I posted around and do it with the height instead. You don't need two lists, you need only one. <block myblock> / trials = [1-2 = mytrial] </block> <trial mytrial> / ontrialbegin = [picture.mypicture.height = list.heights.nextvalue;] / stimulusframes = [1=mypicture] / validresponse = (57) </trial> <picture mypicture> / items = myitems / height = 0% / width = 40% / position = (50%, 50%) </picture> <list heights> / items = (40%, 80%) / selectionmode = picture.mypicture.nextindex </list> <item myitems> / 1 = "01.jpg" / 2 = "02.jpg" </item> Run this, and you'll find that the width is now constant, while the height var
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JuliaJuliaJulia
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Group: Forum Members
Posts: 24,
Visits: 82
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+x+x+x+x[quote]If you want the width to be fixed, but the height to vary, that works in the same way. Ah, so I will create another list element, so that I have in sum two list elements: on for the width and one for the height. I just have problems to understand this pice of code: <picture mypicture>/ items = myitems/ height = 80%/ width = 0%/ position = (50%, 50%)</picture><list widths>/ items = (80%, 40%)/ selectionmode = picture.mypicture.nextindex</list>
For the first item ("01.jpg"; so the horizontal image) the height is set to 80% and the width also to 80%. But that shouldn't be so: The width should be set to 80% and the hight should be allowed to vary... For the second item ("02.jpg"; so the horizontal image) the height is set to 80% and the width to 40%. That also shouldn't be so: The hight should be set to 80% and the width should be allowed to vary and shouldn't be fixed to 40%... Is there a possibility to do that? Best Julia Just flip what I illustrated for the width in the example I posted around and do it with the height instead. You don't need two lists, you need only one. <block myblock> / trials = [1-2 = mytrial] </block> <trial mytrial> / ontrialbegin = [picture.mypicture.height = list.heights.nextvalue;] / stimulusframes = [1=mypicture] / validresponse = (57) </trial> <picture mypicture> / items = myitems / height = 0% / width = 40% / position = (50%, 50%) </picture> <list heights> / items = (40%, 80%) / selectionmode = picture.mypicture.nextindex </list> <item myitems> / 1 = "01.jpg" / 2 = "02.jpg" </item> Run this, and you'll find that the width is now constant, while the height var Thanks for your code! I think your code only works because your image 1 is a square, but in my case image 1 looks like "The Annuciation.jpg" and image 2 like "Eight_Famous_Sights_of_Omi.jpg". In your case image 1 is a square, so a hight of 40% and a width of 40% works...
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JuliaJuliaJulia
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Group: Forum Members
Posts: 24,
Visits: 82
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+x+x+x+x+x[quote]If you want the width to be fixed, but the height to vary, that works in the same way. Ah, so I will create another list element, so that I have in sum two list elements: on for the width and one for the height. I just have problems to understand this pice of code: <picture mypicture>/ items = myitems/ height = 80%/ width = 0%/ position = (50%, 50%)</picture><list widths>/ items = (80%, 40%)/ selectionmode = picture.mypicture.nextindex</list>
For the first item ("01.jpg"; so the horizontal image) the height is set to 80% and the width also to 80%. But that shouldn't be so: The width should be set to 80% and the hight should be allowed to vary... For the second item ("02.jpg"; so the horizontal image) the height is set to 80% and the width to 40%. That also shouldn't be so: The hight should be set to 80% and the width should be allowed to vary and shouldn't be fixed to 40%... Is there a possibility to do that? Best Julia Just flip what I illustrated for the width in the example I posted around and do it with the height instead. You don't need two lists, you need only one. <block myblock> / trials = [1-2 = mytrial] </block> <trial mytrial> / ontrialbegin = [picture.mypicture.height = list.heights.nextvalue;] / stimulusframes = [1=mypicture] / validresponse = (57) </trial> <picture mypicture> / items = myitems / height = 0% / width = 40% / position = (50%, 50%) </picture> <list heights> / items = (40%, 80%) / selectionmode = picture.mypicture.nextindex </list> <item myitems> / 1 = "01.jpg" / 2 = "02.jpg" </item> Run this, and you'll find that the width is now constant, while the height var Thanks for your code! I think your code only works because your image 1 is a square, but in my case image 1 looks like "The Annuciation.jpg" and image 2 like "Eight_Famous_Sights_of_Omi.jpg". In your case image 1 is a square, so a hight of 40% and a width of 40% works... Sorry, the second image cant be loaded, here is the link: https://upload.wikimedia.org/wikipedia/commons/2/2c/Eight_Famous_Sights_of_Omi_by_Imamura_Shiko_%28Tokyo_National_Museum%29.jpg
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Dave
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Group: Administrators
Posts: 12K,
Visits: 98K
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+x+x+x+x+x+x[quote]If you want the width to be fixed, but the height to vary, that works in the same way. Ah, so I will create another list element, so that I have in sum two list elements: on for the width and one for the height. I just have problems to understand this pice of code: <picture mypicture>/ items = myitems/ height = 80%/ width = 0%/ position = (50%, 50%)</picture><list widths>/ items = (80%, 40%)/ selectionmode = picture.mypicture.nextindex</list>
For the first item ("01.jpg"; so the horizontal image) the height is set to 80% and the width also to 80%. But that shouldn't be so: The width should be set to 80% and the hight should be allowed to vary... For the second item ("02.jpg"; so the horizontal image) the height is set to 80% and the width to 40%. That also shouldn't be so: The hight should be set to 80% and the width should be allowed to vary and shouldn't be fixed to 40%... Is there a possibility to do that? Best Julia Just flip what I illustrated for the width in the example I posted around and do it with the height instead. You don't need two lists, you need only one. <block myblock> / trials = [1-2 = mytrial] </block> <trial mytrial> / ontrialbegin = [picture.mypicture.height = list.heights.nextvalue;] / stimulusframes = [1=mypicture] / validresponse = (57) </trial> <picture mypicture> / items = myitems / height = 0% / width = 40% / position = (50%, 50%) </picture> <list heights> / items = (40%, 80%) / selectionmode = picture.mypicture.nextindex </list> <item myitems> / 1 = "01.jpg" / 2 = "02.jpg" </item> Run this, and you'll find that the width is now constant, while the height var Thanks for your code! I think your code only works because your image 1 is a square, but in my case image 1 looks like "The Annuciation.jpg" and image 2 like "Eight_Famous_Sights_of_Omi.jpg". In your case image 1 is a square, so a hight of 40% and a width of 40% works... Sorry, the second image cant be loaded, here is the link: https://upload.wikimedia.org/wikipedia/commons/2/2c/Eight_Famous_Sights_of_Omi_by_Imamura_Shiko_%28Tokyo_National_Museum%29.jpg You should adjust the values in the list such that they suit *your* images.
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JuliaJuliaJulia
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Group: Forum Members
Posts: 24,
Visits: 82
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+x+x+x+x+x+x+x[quote]If you want the width to be fixed, but the height to vary, that works in the same way. Ah, so I will create another list element, so that I have in sum two list elements: on for the width and one for the height. I just have problems to understand this pice of code: <picture mypicture>/ items = myitems/ height = 80%/ width = 0%/ position = (50%, 50%)</picture><list widths>/ items = (80%, 40%)/ selectionmode = picture.mypicture.nextindex</list>
For the first item ("01.jpg"; so the horizontal image) the height is set to 80% and the width also to 80%. But that shouldn't be so: The width should be set to 80% and the hight should be allowed to vary... For the second item ("02.jpg"; so the horizontal image) the height is set to 80% and the width to 40%. That also shouldn't be so: The hight should be set to 80% and the width should be allowed to vary and shouldn't be fixed to 40%... Is there a possibility to do that? Best Julia Just flip what I illustrated for the width in the example I posted around and do it with the height instead. You don't need two lists, you need only one. <block myblock> / trials = [1-2 = mytrial] </block> <trial mytrial> / ontrialbegin = [picture.mypicture.height = list.heights.nextvalue;] / stimulusframes = [1=mypicture] / validresponse = (57) </trial> <picture mypicture> / items = myitems / height = 0% / width = 40% / position = (50%, 50%) </picture> <list heights> / items = (40%, 80%) / selectionmode = picture.mypicture.nextindex </list> <item myitems> / 1 = "01.jpg" / 2 = "02.jpg" </item> Run this, and you'll find that the width is now constant, while the height var Thanks for your code! I think your code only works because your image 1 is a square, but in my case image 1 looks like "The Annuciation.jpg" and image 2 like "Eight_Famous_Sights_of_Omi.jpg". In your case image 1 is a square, so a hight of 40% and a width of 40% works... Sorry, the second image cant be loaded, here is the link: https://upload.wikimedia.org/wikipedia/commons/2/2c/Eight_Famous_Sights_of_Omi_by_Imamura_Shiko_%28Tokyo_National_Museum%29.jpg You should adjust the values in the list such that they suit *your* images. I'm sorry for being so silly but that still doesn't make sense to me. Let's take this code: <block myblock> / trials = [1-2 = mytrial] </block> <trial mytrial> / ontrialbegin = [picture.mypicture.width = list.widths.nextvalue;] / stimulusframes = [1=mypicture] / validresponse = (57) </trial> <picture mypicture> / items = myitems / height = 80% / width = 0% / position = (50%, 50%) </picture> <list widths> / items = (80%, 40%) / selectionmode = picture.mypicture.nextindex </list> <item myitems> / 1 = "01.jpg" / 2 = "02.jpg" </item> --------------------------------------------------------------------------------- For both items the hight is 80% of the screen right? And only the widths varies (80% for the first picture and 40% for the second picture)?
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Dave
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Group: Administrators
Posts: 12K,
Visits: 98K
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+xI'm sorry for being so silly but that still doesn't make sense to me. Let's take this code: <block myblock> / trials = [1-2 = mytrial] </block> <trial mytrial> / ontrialbegin = [picture.mypicture.width = list.widths.nextvalue;] / stimulusframes = [1=mypicture] / validresponse = (57) </trial> <picture mypicture> / items = myitems / height = 80% / width = 0% / position = (50%, 50%) </picture> <list widths> / items = (80%, 40%) / selectionmode = picture.mypicture.nextindex </list> <item myitems> / 1 = "01.jpg" / 2 = "02.jpg" </item> --------------------------------------------------------------------------------- For both items the hight is 80% of the screen right? And only the widths varies (80% for the first picture and 40% for the second picture)? > For both items the hight is 80% of the screen right? And only the widths varies (80% for the first picture and 40% for the second picture)? Yes. The height of the <picture> element is set to 80% here <picture mypicture> / items = myitems / height = 80%/ width = 0% / position = (50%, 50%) </picture> and nowhere is it changed. The width is set on a trial-by-trial basis here <trial mytrial> / ontrialbegin = [picture.mypicture. width = list. widths.nextvalue;] / stimulusframes = [1=mypicture] / validresponse = (57) </trial> and it is sampled from the <list> element. Which value, i.e. width, the list returns depends on the picture item the trial will display. Do keep in mind one thing: Inquisit will not, under any circumstances, distort the original image's dimensions. They will remain intact, i.e. Inquisit will not "stretch" an image just because you set an excessive width or height. I.e. suppose you have an image that is 400 pixels wide, and 300 pixels high, then -- not matter what you do, the 4:3 width/height ratio will always be preserved, even if you set the <picture> element's dimensions to something absurd like width = 5% & height = 90%.
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JuliaJuliaJulia
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Group: Forum Members
Posts: 24,
Visits: 82
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+x+xI'm sorry for being so silly but that still doesn't make sense to me. Let's take this code: <block myblock> / trials = [1-2 = mytrial] </block> <trial mytrial> / ontrialbegin = [picture.mypicture.width = list.widths.nextvalue;] / stimulusframes = [1=mypicture] / validresponse = (57) </trial> <picture mypicture> / items = myitems / height = 80% / width = 0% / position = (50%, 50%) </picture> <list widths> / items = (80%, 40%) / selectionmode = picture.mypicture.nextindex </list> <item myitems> / 1 = "01.jpg" / 2 = "02.jpg" </item> --------------------------------------------------------------------------------- For both items the hight is 80% of the screen right? And only the widths varies (80% for the first picture and 40% for the second picture)? > For both items the hight is 80% of the screen right? And only the widths varies (80% for the first picture and 40% for the second picture)? Yes. The height of the <picture> element is set to 80% here <picture mypicture> / items = myitems / height = 80%/ width = 0% / position = (50%, 50%) </picture> and nowhere is it changed. The width is set on a trial-by-trial basis here <trial mytrial> / ontrialbegin = [picture.mypicture. width = list. widths.nextvalue;] / stimulusframes = [1=mypicture] / validresponse = (57) </trial> and it is sampled from the <list> element. Which value, i.e. width, the list returns depends on the picture item the trial will display. Do keep in mind one thing: Inquisit will not, under any circumstances, distort the original image's dimensions. They will remain intact, i.e. Inquisit will not "stretch" an image just because you set an excessive width or height. I.e. suppose you have an image that is 400 pixels wide, and 300 pixels high, then -- not matter what you do, the 4:3 width/height ratio will always be preserved, even if you set the <picture> element's dimensions to something absurd like width = 5% & height = 90%. Hey Dave, thanks so much for this explanation and your help! I didn't know that Inquisit doesn't distort the image's dimensions. Know everything makes completely sense too me!!!!!! And it works! Thanks and best, Julia
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