How do I randomize the order of may blocks except the first one ?

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How do I randomize the order of may blocks except the first one ?

How do I randomize the order of may blocks except the first one ?

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labdandeneau@gmail.com	labdandeneau@gmail.com posted 5 Years Ago HOT Topic Details Share Topic
Group: Forum Members Posts: 12, Visits: 73	Hey, I tried to make it so all participants in my task would first all get the same practice block but then have a different order for the other blocks depending. Is this the accurate syntax for it ? <expt> / subjects = (1 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory; 3 = wordmemory2; 4 = wordmemory3;] </expt> <expt> / subjects = (2 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory; 3 = wordmemory3; 4 = wordmemory2;] </expt> <expt> / subjects = (3 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory2; 3 = wordmemory3; 4 = wordmemory;] </expt> <expt> / subjects = (4 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory2; 3 = wordmemory; 4 = wordmemory3;] </expt> <expt> / subjects = (5 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory3; 3 = wordmemory; 4 = wordmemory2;] </expt> <expt> / subjects = (6 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory3; 3 = wordmemory2; 4 = wordmemory;] Attachments TheWordMemoryTaskModified2DATA.iqx (435 views, 65.00 KB)
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Dave	Dave posted 5 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 12K, Visits: 98K	+x labdandeneau@gmail.com - Monday, March 4, 2019 Hey, I tried to make it so all participants in my task would first all get the same practice block but then have a different order for the other blocks depending. Is this the accurate syntax for it ? <expt> / subjects = (1 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory; 3 = wordmemory2; 4 = wordmemory3;] </expt> <expt> / subjects = (2 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory; 3 = wordmemory3; 4 = wordmemory2;] </expt> <expt> / subjects = (3 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory2; 3 = wordmemory3; 4 = wordmemory;] </expt> <expt> / subjects = (4 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory2; 3 = wordmemory; 4 = wordmemory3;] </expt> <expt> / subjects = (5 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory3; 3 = wordmemory; 4 = wordmemory2;] </expt> <expt> / subjects = (6 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory3; 3 = wordmemory2; 4 = wordmemory;] If you want to treat the order of non-practice blocks (wordmemory to wordmemory3) as a between-subjects factor, then yes, that would be the way to do it. If you merely want to randomize the order (not treating it as a systematic between-subjects manipulation), then you would simply make do with a single <expt> element: <expt> / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2-4 = noreplace(wordmemory, wordmemory2, wordmemory3)] </expt>
	Reply Like 34
labdandeneau@gmail.com	labdandeneau@gmail.com posted 5 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 12, Visits: 73	+x Dave - 3/4/2019 +x labdandeneau@gmail.com - Monday, March 4, 2019 Hey, I tried to make it so all participants in my task would first all get the same practice block but then have a different order for the other blocks depending. Is this the accurate syntax for it ? <expt> / subjects = (1 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory; 3 = wordmemory2; 4 = wordmemory3;] </expt> <expt> / subjects = (2 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory; 3 = wordmemory3; 4 = wordmemory2;] </expt> <expt> / subjects = (3 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory2; 3 = wordmemory3; 4 = wordmemory;] </expt> <expt> / subjects = (4 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory2; 3 = wordmemory; 4 = wordmemory3;] </expt> <expt> / subjects = (5 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory3; 3 = wordmemory; 4 = wordmemory2;] </expt> <expt> / subjects = (6 of 6) / groupassignment = groupnumber / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2 = wordmemory3; 3 = wordmemory2; 4 = wordmemory;] If you want to treat the order of non-practice blocks (wordmemory to wordmemory3) as a between-subjects factor, then yes, that would be the way to do it. If you merely want to randomize the order (not treating it as a systematic between-subjects manipulation), then you would simply make do with a single <expt> element: <expt> / postinstructions = (end) / onexptend = [values.completed = 1] / blocks = [1 = wordmemory0; 2-4 = noreplace(wordmemory, wordmemory2, wordmemory3)] </expt> thank you I wanted it to be a between-subject factor. I sent a link to my experiment to a few people via email but they all encountered the same block order, why is that?
	Reply Like 34
Dave	Dave posted 5 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 12K, Visits: 98K	+x labdandeneau@gmail.com - 7/22/2019 thank you I wanted it to be a between-subject factor. I sent a link to my experiment to a few people via email but they all encountered the same block order, why is that? I cannot answer that without (a) the relevant code from the script and (b) the link you sent out.
	Reply Like 30
labdandeneau@gmail.com	labdandeneau@gmail.com posted 5 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 12, Visits: 73	+x Dave - 7/22/2019 +x labdandeneau@gmail.com - 7/22/2019 thank you I wanted it to be a between-subject factor. I sent a link to my experiment to a few people via email but they all encountered the same block order, why is that? I cannot answer that without (a) the relevant code from the script and (b) the link you sent out. I have just sent you the link with the file so you can access the script. I could not copy paste the relevant syntax in the op however.
	Reply Like 33
Dave	Dave posted 5 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 12K, Visits: 98K	+x labdandeneau@gmail.com - 8/8/2019 +x Dave - 7/22/2019 +x labdandeneau@gmail.com - 7/22/2019 thank you I wanted it to be a between-subject factor. I sent a link to my experiment to a few people via email but they all encountered the same block order, why is that? I cannot answer that without (a) the relevant code from the script and (b) the link you sent out. I have just sent you the link with the file so you can access the script. I could not copy paste the relevant syntax in the op however. Thank you -- I have responded via private message.
	Reply Like 33