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Maleza
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Group: Forum Members
Posts: 8,
Visits: 15
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Dear all,
The following 32 numbers should appear randomly to 50% at the top andto 50% at the bottom of the PC screen. The randomized seection works fine, but is it the cae that the numbers are presented equally at the bottom and top (50% top/50/bottom)? Thank you for your help!
<list values>
/ items = ("480 m", "8850 m", "5900 m", "2960 m", "120 m", "70 m", "160 m ", "370 m", "320 m", "440 m", "830 m", "570 m", "1640 m", "250 m", "210 m", "360 m",
"1170 m", "3770 m", "120 kg", "120 ltr", "4130 km", "1840 km", "2150", "190", "870 Tage", "70 °C", "2400", "660", "190", "5200", "120 ltr", "10000 ltr")
/ selectionmode = list.questions.currentindex
</list>
*****here I define where these values appear*****
<counter vpositions1>
/ items = (95,5)
/ select = noreplace
</counter>
Best,
Lea
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Dave
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Group: Administrators
Posts: 12K,
Visits: 98K
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+xDear all, The following 32 numbers should appear randomly to 50% at the top andto 50% at the bottom of the PC screen. The randomized seection works fine, but is it the cae that the numbers are presented equally at the bottom and top (50% top/50/bottom)? Thank you for your help! <list values> / items = ("480 m", "8850 m", "5900 m", "2960 m", "120 m", "70 m", "160 m ", "370 m", "320 m", "440 m", "830 m", "570 m", "1640 m", "250 m", "210 m", "360 m", "1170 m", "3770 m", "120 kg", "120 ltr", "4130 km", "1840 km", "2150", "190", "870 Tage", "70 °C", "2400", "660", "190", "5200", "120 ltr", "10000 ltr") / selectionmode = list.questions.currentindex </list> *****here I define where these values appear***** <counter vpositions1> / items = (95,5) / select = noreplace </counter> Best, Lea <counter vpositions1> / items = (95,5) / select = noreplace </counter> You have two items in your counter and you're sampling without replacement. Suppose in the first trial the position sampled is 5. Then, in the second trial, the position sampled will necessarily be 95. You're sampling without replacement, after all. I.e. for any set of two consecutive trials (1 and 2; 3 and 4; 5 and 6; etc.), you'll have the stimulus displayed 1 x in the top position and 1 x in the bottom position.
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Maleza
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Group: Forum Members
Posts: 8,
Visits: 15
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+x+xDear all, The following 32 numbers should appear randomly to 50% at the top andto 50% at the bottom of the PC screen. The randomized seection works fine, but is it the cae that the numbers are presented equally at the bottom and top (50% top/50/bottom)? Thank you for your help! <list values> / items = ("480 m", "8850 m", "5900 m", "2960 m", "120 m", "70 m", "160 m ", "370 m", "320 m", "440 m", "830 m", "570 m", "1640 m", "250 m", "210 m", "360 m", "1170 m", "3770 m", "120 kg", "120 ltr", "4130 km", "1840 km", "2150", "190", "870 Tage", "70 °C", "2400", "660", "190", "5200", "120 ltr", "10000 ltr") / selectionmode = list.questions.currentindex </list> *****here I define where these values appear***** <counter vpositions1> / items = (95,5) / select = noreplace </counter> Best, Lea <counter vpositions1> / items = (95,5) / select = noreplace </counter> You have two items in your counter and you're sampling without replacement. Suppose in the first trial the position sampled is 5. Then, in the second trial, the position sampled will necessarily be 95. You're sampling without replacement, after all. I.e. for any set of two consecutive trials (1 and 2; 3 and 4; 5 and 6; etc.), you'll have the stimulus displayed 1 x in the top position and 1 x in the bottom position. Okay I understand how it works. For my purpuse I want it actually different: I want that the numbers appear completely random at the top or ottom, meaning that a number could appear tthree or four times in a row at the to for examplep. But still, over all 32 trials, it should be 50% top and 50% bottom. Could you please tell me how to do it as I need to run the experiment tomorrow ;). Thank you very much.
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Dave
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Group: Administrators
Posts: 12K,
Visits: 98K
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+x+x+xDear all, The following 32 numbers should appear randomly to 50% at the top andto 50% at the bottom of the PC screen. The randomized seection works fine, but is it the cae that the numbers are presented equally at the bottom and top (50% top/50/bottom)? Thank you for your help! <list values> / items = ("480 m", "8850 m", "5900 m", "2960 m", "120 m", "70 m", "160 m ", "370 m", "320 m", "440 m", "830 m", "570 m", "1640 m", "250 m", "210 m", "360 m", "1170 m", "3770 m", "120 kg", "120 ltr", "4130 km", "1840 km", "2150", "190", "870 Tage", "70 °C", "2400", "660", "190", "5200", "120 ltr", "10000 ltr") / selectionmode = list.questions.currentindex </list> *****here I define where these values appear***** <counter vpositions1> / items = (95,5) / select = noreplace </counter> Best, Lea <counter vpositions1> / items = (95,5) / select = noreplace </counter> You have two items in your counter and you're sampling without replacement. Suppose in the first trial the position sampled is 5. Then, in the second trial, the position sampled will necessarily be 95. You're sampling without replacement, after all. I.e. for any set of two consecutive trials (1 and 2; 3 and 4; 5 and 6; etc.), you'll have the stimulus displayed 1 x in the top position and 1 x in the bottom position. Okay I understand how it works. For my purpuse I want it actually different: I want that the numbers appear completely random at the top or ottom, meaning that a number could appear tthree or four times in a row at the to for examplep. But still, over all 32 trials, it should be 50% top and 50% bottom. Could you please tell me how to do it as I need to run the experiment tomorrow ;). Thank you very much. If you run 32 trials and want 16 x top and 16 x bottom, then that's just what you need to enter as items in the counter: <counter vpositions1> / items = (95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5) / select = noreplace </counter>
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Maleza
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Group: Forum Members
Posts: 8,
Visits: 15
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+x+x+x+xDear all, The following 32 numbers should appear randomly to 50% at the top andto 50% at the bottom of the PC screen. The randomized seection works fine, but is it the cae that the numbers are presented equally at the bottom and top (50% top/50/bottom)? Thank you for your help! <list values> / items = ("480 m", "8850 m", "5900 m", "2960 m", "120 m", "70 m", "160 m ", "370 m", "320 m", "440 m", "830 m", "570 m", "1640 m", "250 m", "210 m", "360 m", "1170 m", "3770 m", "120 kg", "120 ltr", "4130 km", "1840 km", "2150", "190", "870 Tage", "70 °C", "2400", "660", "190", "5200", "120 ltr", "10000 ltr") / selectionmode = list.questions.currentindex </list> *****here I define where these values appear***** <counter vpositions1> / items = (95,5) / select = noreplace </counter> Best, Lea <counter vpositions1> / items = (95,5) / select = noreplace </counter> You have two items in your counter and you're sampling without replacement. Suppose in the first trial the position sampled is 5. Then, in the second trial, the position sampled will necessarily be 95. You're sampling without replacement, after all. I.e. for any set of two consecutive trials (1 and 2; 3 and 4; 5 and 6; etc.), you'll have the stimulus displayed 1 x in the top position and 1 x in the bottom position. Okay I understand how it works. For my purpuse I want it actually different: I want that the numbers appear completely random at the top or ottom, meaning that a number could appear tthree or four times in a row at the to for examplep. But still, over all 32 trials, it should be 50% top and 50% bottom. Could you please tell me how to do it as I need to run the experiment tomorrow ;). Thank you very much. If you run 32 trials and want 16 x top and 16 x bottom, then that's just what you need to enter as items in the counter: <counter vpositions1> / items = (95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5) / select = noreplace </counter> Ah true, I see! Thanks
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