morgan_w


Group: Forum Members
Posts: 5,
Visits: 39

Hello! Sorry if this question has already been asked and answered, I haven't had much luck finding it. I've been hoping to replicate a response button setup with 8 options that are symmetrically placed around the center of the screen, but the eight options are related in 4 pairs. The standard for this involves triangular buttons in shapes and orientations roughly like the attached image, so that each pair of related options forms a coloured box. At the moment I've noticed that Inquisit is treating the triangles as entire rectangles, which would make the buttons overlap. Thanks for the help! Best, Morgan



Dave


Group: Administrators
Posts: 9.6K,
Visits: 44K

+xHello! Sorry if this question has already been asked and answered, I haven't had much luck finding it. I've been hoping to replicate a response button setup with 8 options that are symmetrically placed around the center of the screen, but the eight options are related in 4 pairs. The standard for this involves triangular buttons in shapes and orientations roughly like the attached image, so that each pair of related options forms a coloured box. At the moment I've noticed that Inquisit is treating the triangles as entire rectangles, which would make the buttons overlap. Thanks for the help! Best, Morgan I assume you're using <picture> elements for the triangles, which is why they're treated as rectangles. Even if an image displays a triangle, the image itself is still a full rectangle. You would not have that problem with <shape> elements: <shape a> / shape = triangle / size = (500px,500px) / color = orangered </shape> <shape b> / shape = rectangle / size = (500px,500px) / color = orange </shape> <trial mytrial> / stimulusframes = [1=b,a] / inputdevice = mouse / validresponse = (a,b) </trial> The above will differentiate between a click in shape A vs shape B just fine, however, creating an array like the one you want is not possible with overlaid <shape>s. You could build an array with rectangles as a simple workaround. <shape a> / shape = rectangle / size = (500px,250px) / color = orangered / valign = top </shape> <shape b> / shape = rectangle / size = (500px,250px) / color = orange / valign = bottom </shape> <trial mytrial> / stimulusframes = [1=b,a] / inputdevice = mouse / validresponse = (a,b) </trial> In sum, there certainly is no easy way to do this, if triangles are an absolute requirement. In theory, you would build a set of custom expressions that perform a triangle test, but the math is not entirely trivial (e.g. https://stackoverflow.com/questions/2049582/howtodetermineifapointisina2dtriangle ).



morgan_w


Group: Forum Members
Posts: 5,
Visits: 39

+x+xHello! Sorry if this question has already been asked and answered, I haven't had much luck finding it. I've been hoping to replicate a response button setup with 8 options that are symmetrically placed around the center of the screen, but the eight options are related in 4 pairs. The standard for this involves triangular buttons in shapes and orientations roughly like the attached image, so that each pair of related options forms a coloured box. At the moment I've noticed that Inquisit is treating the triangles as entire rectangles, which would make the buttons overlap. Thanks for the help! Best, Morgan I assume you're using <picture> elements for the triangles, which is why they're treated as rectangles. Even if an image displays a triangle, the image itself is still a full rectangle. You would not have that problem with <shape> elements: <shape a> / shape = triangle / size = (500px,500px) / color = orangered </shape> <shape b> / shape = rectangle / size = (500px,500px) / color = orange </shape> <trial mytrial> / stimulusframes = [1=b,a] / inputdevice = mouse / validresponse = (a,b) </trial> The above will differentiate between a click in shape A vs shape B just fine, however, creating an array like the one you want is not possible with overlaid <shape>s. You could build an array with rectangles as a simple workaround. <shape a> / shape = rectangle / size = (500px,250px) / color = orangered / valign = top </shape> <shape b> / shape = rectangle / size = (500px,250px) / color = orange / valign = bottom </shape> <trial mytrial> / stimulusframes = [1=b,a] / inputdevice = mouse / validresponse = (a,b) </trial> In sum, there certainly is no easy way to do this, if triangles are an absolute requirement. In theory, you would build a set of custom expressions that perform a triangle test, but the math is not entirely trivial (e.g. https://stackoverflow.com/questions/2049582/howtodetermineifapointisina2dtriangle ). Thanks a lot Dave, really appreciate the options. Will play around with boxes to see if I can get a satisfactory compromise before I attempt the maths!



morgan_w


Group: Forum Members
Posts: 5,
Visits: 39

+x+x+xHello! Sorry if this question has already been asked and answered, I haven't had much luck finding it. I've been hoping to replicate a response button setup with 8 options that are symmetrically placed around the center of the screen, but the eight options are related in 4 pairs. The standard for this involves triangular buttons in shapes and orientations roughly like the attached image, so that each pair of related options forms a coloured box. At the moment I've noticed that Inquisit is treating the triangles as entire rectangles, which would make the buttons overlap. Thanks for the help! Best, Morgan I assume you're using <picture> elements for the triangles, which is why they're treated as rectangles. Even if an image displays a triangle, the image itself is still a full rectangle. You would not have that problem with <shape> elements: <shape a> / shape = triangle / size = (500px,500px) / color = orangered </shape> <shape b> / shape = rectangle / size = (500px,500px) / color = orange </shape> <trial mytrial> / stimulusframes = [1=b,a] / inputdevice = mouse / validresponse = (a,b) </trial> The above will differentiate between a click in shape A vs shape B just fine, however, creating an array like the one you want is not possible with overlaid <shape>s. You could build an array with rectangles as a simple workaround. <shape a> / shape = rectangle / size = (500px,250px) / color = orangered / valign = top </shape> <shape b> / shape = rectangle / size = (500px,250px) / color = orange / valign = bottom </shape> <trial mytrial> / stimulusframes = [1=b,a] / inputdevice = mouse / validresponse = (a,b) </trial> In sum, there certainly is no easy way to do this, if triangles are an absolute requirement. In theory, you would build a set of custom expressions that perform a triangle test, but the math is not entirely trivial (e.g. https://stackoverflow.com/questions/2049582/howtodetermineifapointisina2dtriangle ). Thanks a lot Dave, really appreciate the options. Will play around with boxes to see if I can get a satisfactory compromise before I attempt the maths! Hi Dave, Tried to do the maths in the end (thanks for the link! went with barycentric coordinates) and got it working for a single triangle pretty easily. However, my current attempt will not let me distinguish between two triangles that are placed together to form a square as in any corner of the image above, even though I have triangle tests for both triangles individually. Any ideas to tie each triangle test as the condition for each triangle as a response? I'll include what I've whipped up so far: <picture triangle1> / items = ("practice_triangle.png") / position = (50,50) </picture> <picture triangle2> / items = ("practice_triangle2.png") / position = (50,50) </picture> <expressions triangle1> / x1 = picture.triangle1.left / y1 = picture.triangle1.bottom / x2 = picture.triangle1.left / y2 = picture.triangle1.top / x3 = picture.triangle1.right / y3 = picture.triangle1.bottom / a = ((expressions.y2  expressions.y3)*(mouse.x  expressions.x3) + (expressions.x3  expressions.x2)*(mouse.y  expressions.y3)) / ((expressions.y2  expressions.y3)*(expressions.x1  expressions.x3)+(expressions.x3  expressions.x2)*(expressions.y1  expressions.y3)) / b = ((expressions.y3  expressions.y1)*(mouse.x  expressions.x3) + (expressions.x1  expressions.x3)*(mouse.y  expressions.y3)) / ((expressions.y2  expressions.y3)*(expressions.x1  expressions.x3)+(expressions.x3  expressions.x2)*(expressions.y1  expressions.y3)) / c = 1  expressions.a  expressions.b </expressions> <expressions triangle2> / x12 = picture.triangle2.left / y12 = picture.triangle2.top / x22 = picture.triangle2.right / y22 = picture.triangle2.top / x32 = picture.triangle2.right / y32 = picture.triangle2.bottom / a2 = ((expressions.y22  expressions.y32)*(mouse.x  expressions.x32) + (expressions.x32  expressions.x22)*(mouse.y  expressions.y32)) / ((expressions.y22  expressions.y32)*(expressions.x12  expressions.x32)+(expressions.x32  expressions.x22)*(expressions.y12  expressions.y32)) / b2 = ((expressions.y32  expressions.y12)*(mouse.x  expressions.x32) + (expressions.x12  expressions.x32)*(mouse.y  expressions.y32)) / ((expressions.y22  expressions.y32)*(expressions.x12  expressions.x32)+(expressions.x32  expressions.x22)*(expressions.y12  expressions.y32)) / c2 = 1  expressions.a2  expressions.b2 </expressions> <text report> / items = ("<%mouse.x%>, <%mouse.y%>, <%expressions.a%>, <%expressions.b%>, <%expressions.c%>", <%expressions.a2%>, <%expressions.b2%>, <%expressions.c2%> / position = (50, 15) </text> <trial mytrial> / stimulusframes = [1 = triangle1, triangle2, report] / validresponse = (picture.triangle1, picture.triangle2) / inputdevice = mouse / isvalidresponse = [ 0<=expressions.a && expressions.a <= 1 && 0 <= expressions.b && expressions.b <= 1 && 0 <= expressions.c && expressions.c <= 1  0<=expressions.a2 && expressions.a2 <= 1 && 0 <= expressions.b2 && expressions.b2 <= 1 && 0 <= expressions.c2 && expressions.c2 <= 1 ] </trial> <block myblock> / trials = [13 = mytrial] </block> Yellow triangle is practice_triangle1.png and green is practice_triangle2.png At the moment, as I understand it, the  condition in the / isvalidresponse is making the triangle test effectively useless, and I can click on either 'triangle' but the response registered is the first image. Does anyone have any ideas to tie the mouse location to a specific triangle, even though they overlap? Cheers, Morgan



Dave


Group: Administrators
Posts: 9.6K,
Visits: 44K

+x+x+x+xHello! Sorry if this question has already been asked and answered, I haven't had much luck finding it. I've been hoping to replicate a response button setup with 8 options that are symmetrically placed around the center of the screen, but the eight options are related in 4 pairs. The standard for this involves triangular buttons in shapes and orientations roughly like the attached image, so that each pair of related options forms a coloured box. At the moment I've noticed that Inquisit is treating the triangles as entire rectangles, which would make the buttons overlap. Thanks for the help! Best, Morgan I assume you're using <picture> elements for the triangles, which is why they're treated as rectangles. Even if an image displays a triangle, the image itself is still a full rectangle. You would not have that problem with <shape> elements: <shape a> / shape = triangle / size = (500px,500px) / color = orangered </shape> <shape b> / shape = rectangle / size = (500px,500px) / color = orange </shape> <trial mytrial> / stimulusframes = [1=b,a] / inputdevice = mouse / validresponse = (a,b) </trial> The above will differentiate between a click in shape A vs shape B just fine, however, creating an array like the one you want is not possible with overlaid <shape>s. You could build an array with rectangles as a simple workaround. <shape a> / shape = rectangle / size = (500px,250px) / color = orangered / valign = top </shape> <shape b> / shape = rectangle / size = (500px,250px) / color = orange / valign = bottom </shape> <trial mytrial> / stimulusframes = [1=b,a] / inputdevice = mouse / validresponse = (a,b) </trial> In sum, there certainly is no easy way to do this, if triangles are an absolute requirement. In theory, you would build a set of custom expressions that perform a triangle test, but the math is not entirely trivial (e.g. https://stackoverflow.com/questions/2049582/howtodetermineifapointisina2dtriangle ). Thanks a lot Dave, really appreciate the options. Will play around with boxes to see if I can get a satisfactory compromise before I attempt the maths! Hi Dave, Tried to do the maths in the end (thanks for the link! went with barycentric coordinates) and got it working for a single triangle pretty easily. However, my current attempt will not let me distinguish between two triangles that are placed together to form a square as in any corner of the image above, even though I have triangle tests for both triangles individually. Any ideas to tie each triangle test as the condition for each triangle as a response? I'll include what I've whipped up so far: <picture triangle1> / items = ("practice_triangle.png") / position = (50,50) </picture> <picture triangle2> / items = ("practice_triangle2.png") / position = (50,50) </picture> <expressions triangle1> / x1 = picture.triangle1.left / y1 = picture.triangle1.bottom / x2 = picture.triangle1.left / y2 = picture.triangle1.top / x3 = picture.triangle1.right / y3 = picture.triangle1.bottom / a = ((expressions.y2  expressions.y3)*(mouse.x  expressions.x3) + (expressions.x3  expressions.x2)*(mouse.y  expressions.y3)) / ((expressions.y2  expressions.y3)*(expressions.x1  expressions.x3)+(expressions.x3  expressions.x2)*(expressions.y1  expressions.y3)) / b = ((expressions.y3  expressions.y1)*(mouse.x  expressions.x3) + (expressions.x1  expressions.x3)*(mouse.y  expressions.y3)) / ((expressions.y2  expressions.y3)*(expressions.x1  expressions.x3)+(expressions.x3  expressions.x2)*(expressions.y1  expressions.y3)) / c = 1  expressions.a  expressions.b </expressions> <expressions triangle2> / x12 = picture.triangle2.left / y12 = picture.triangle2.top / x22 = picture.triangle2.right / y22 = picture.triangle2.top / x32 = picture.triangle2.right / y32 = picture.triangle2.bottom / a2 = ((expressions.y22  expressions.y32)*(mouse.x  expressions.x32) + (expressions.x32  expressions.x22)*(mouse.y  expressions.y32)) / ((expressions.y22  expressions.y32)*(expressions.x12  expressions.x32)+(expressions.x32  expressions.x22)*(expressions.y12  expressions.y32)) / b2 = ((expressions.y32  expressions.y12)*(mouse.x  expressions.x32) + (expressions.x12  expressions.x32)*(mouse.y  expressions.y32)) / ((expressions.y22  expressions.y32)*(expressions.x12  expressions.x32)+(expressions.x32  expressions.x22)*(expressions.y12  expressions.y32)) / c2 = 1  expressions.a2  expressions.b2 </expressions> <text report> / items = ("<%mouse.x%>, <%mouse.y%>, <%expressions.a%>, <%expressions.b%>, <%expressions.c%>", <%expressions.a2%>, <%expressions.b2%>, <%expressions.c2%> / position = (50, 15) </text> <trial mytrial> / stimulusframes = [1 = triangle1, triangle2, report] / validresponse = (picture.triangle1, picture.triangle2) / inputdevice = mouse / isvalidresponse = [ 0<=expressions.a && expressions.a <= 1 && 0 <= expressions.b && expressions.b <= 1 && 0 <= expressions.c && expressions.c <= 1  0<=expressions.a2 && expressions.a2 <= 1 && 0 <= expressions.b2 && expressions.b2 <= 1 && 0 <= expressions.c2 && expressions.c2 <= 1 ] </trial> <block myblock> / trials = [13 = mytrial] </block> Yellow triangle is practice_triangle1.png and green is practice_triangle2.png At the moment, as I understand it, the  condition in the / isvalidresponse is making the triangle test effectively useless, and I can click on either 'triangle' but the response registered is the first image. Does anyone have any ideas to tie the mouse location to a specific triangle, even though they overlap? Cheers, Morgan You'll want to do something like this: <picture triangle1> / items = ("practice_triangle1.png") / position = (50,50) </picture> <picture triangle2> / items = ("practice_triangle2.png") / position = (50,50) </picture> <expressions triangle1> / x1 = picture.triangle1.left / y1 = picture.triangle1.bottom / x2 = picture.triangle1.left / y2 = picture.triangle1.top / x3 = picture.triangle1.right / y3 = picture.triangle1.bottom / a = ((expressions.y2  expressions.y3)*(mouse.x  expressions.x3) + (expressions.x3  expressions.x2)*(mouse.y  expressions.y3)) / ((expressions.y2  expressions.y3)*(expressions.x1  expressions.x3)+(expressions.x3  expressions.x2)*(expressions.y1  expressions.y3)) / b = ((expressions.y3  expressions.y1)*(mouse.x  expressions.x3) + (expressions.x1  expressions.x3)*(mouse.y  expressions.y3)) / ((expressions.y2  expressions.y3)*(expressions.x1  expressions.x3)+(expressions.x3  expressions.x2)*(expressions.y1  expressions.y3)) / c = 1  expressions.a  expressions.b </expressions> <expressions triangle2> / x12 = picture.triangle2.left / y12 = picture.triangle2.top / x22 = picture.triangle2.right / y22 = picture.triangle2.top / x32 = picture.triangle2.right / y32 = picture.triangle2.bottom / a2 = ((expressions.y22  expressions.y32)*(mouse.x  expressions.x32) + (expressions.x32  expressions.x22)*(mouse.y  expressions.y32)) / ((expressions.y22  expressions.y32)*(expressions.x12  expressions.x32)+(expressions.x32  expressions.x22)*(expressions.y12  expressions.y32)) / b2 = ((expressions.y32  expressions.y12)*(mouse.x  expressions.x32) + (expressions.x12  expressions.x32)*(mouse.y  expressions.y32)) / ((expressions.y22  expressions.y32)*(expressions.x12  expressions.x32)+(expressions.x32  expressions.x22)*(expressions.y12  expressions.y32)) / c2 = 1  expressions.a2  expressions.b2 </expressions> <text report> / items = ("<%mouse.x%>, <%mouse.y%>, <%expressions.a%>, <%expressions.b%>, <%expressions.c%>, <%expressions.a2%>, <%expressions.b2%>, <%expressions.c2%>") / position = (50, 15) </text> <trial mytrial> / ontrialbegin = [ values.response = ""; ] / stimulusframes = [1 = triangle1, triangle2, report] / validresponse = (lbuttondown) / inputdevice = mouse / isvalidresponse = [ if(0<=expressions.a && expressions.a <= 1 && 0 <= expressions.b && expressions.b <= 1 && 0 <= expressions.c && expressions.c <= 1){ values.response = "triangle1"; true; } else if(0<=expressions.a2 && expressions.a2 <= 1 && 0 <= expressions.b2 && expressions.b2 <= 1 && 0 <= expressions.c2 && expressions.c2 <= 1){ values.response = "triangle2"; true; } ] </trial> <block myblock> / trials = [13 = mytrial] </block> <values> / response = "" </values> <data> / columns = (date time subject group blocknum blockcode trialnum trialcode values.response latency) / separatefiles = true </data>



morgan_w


Group: Forum Members
Posts: 5,
Visits: 39

+x+x+x+x+xHello! Sorry if this question has already been asked and answered, I haven't had much luck finding it. I've been hoping to replicate a response button setup with 8 options that are symmetrically placed around the center of the screen, but the eight options are related in 4 pairs. The standard for this involves triangular buttons in shapes and orientations roughly like the attached image, so that each pair of related options forms a coloured box. At the moment I've noticed that Inquisit is treating the triangles as entire rectangles, which would make the buttons overlap. Thanks for the help! Best, Morgan I assume you're using <picture> elements for the triangles, which is why they're treated as rectangles. Even if an image displays a triangle, the image itself is still a full rectangle. You would not have that problem with <shape> elements: <shape a> / shape = triangle / size = (500px,500px) / color = orangered </shape> <shape b> / shape = rectangle / size = (500px,500px) / color = orange </shape> <trial mytrial> / stimulusframes = [1=b,a] / inputdevice = mouse / validresponse = (a,b) </trial> The above will differentiate between a click in shape A vs shape B just fine, however, creating an array like the one you want is not possible with overlaid <shape>s. You could build an array with rectangles as a simple workaround. <shape a> / shape = rectangle / size = (500px,250px) / color = orangered / valign = top </shape> <shape b> / shape = rectangle / size = (500px,250px) / color = orange / valign = bottom </shape> <trial mytrial> / stimulusframes = [1=b,a] / inputdevice = mouse / validresponse = (a,b) </trial> In sum, there certainly is no easy way to do this, if triangles are an absolute requirement. In theory, you would build a set of custom expressions that perform a triangle test, but the math is not entirely trivial (e.g. https://stackoverflow.com/questions/2049582/howtodetermineifapointisina2dtriangle ). Thanks a lot Dave, really appreciate the options. Will play around with boxes to see if I can get a satisfactory compromise before I attempt the maths! Hi Dave, Tried to do the maths in the end (thanks for the link! went with barycentric coordinates) and got it working for a single triangle pretty easily. However, my current attempt will not let me distinguish between two triangles that are placed together to form a square as in any corner of the image above, even though I have triangle tests for both triangles individually. Any ideas to tie each triangle test as the condition for each triangle as a response? I'll include what I've whipped up so far: <picture triangle1> / items = ("practice_triangle.png") / position = (50,50) </picture> <picture triangle2> / items = ("practice_triangle2.png") / position = (50,50) </picture> <expressions triangle1> / x1 = picture.triangle1.left / y1 = picture.triangle1.bottom / x2 = picture.triangle1.left / y2 = picture.triangle1.top / x3 = picture.triangle1.right / y3 = picture.triangle1.bottom / a = ((expressions.y2  expressions.y3)*(mouse.x  expressions.x3) + (expressions.x3  expressions.x2)*(mouse.y  expressions.y3)) / ((expressions.y2  expressions.y3)*(expressions.x1  expressions.x3)+(expressions.x3  expressions.x2)*(expressions.y1  expressions.y3)) / b = ((expressions.y3  expressions.y1)*(mouse.x  expressions.x3) + (expressions.x1  expressions.x3)*(mouse.y  expressions.y3)) / ((expressions.y2  expressions.y3)*(expressions.x1  expressions.x3)+(expressions.x3  expressions.x2)*(expressions.y1  expressions.y3)) / c = 1  expressions.a  expressions.b </expressions> <expressions triangle2> / x12 = picture.triangle2.left / y12 = picture.triangle2.top / x22 = picture.triangle2.right / y22 = picture.triangle2.top / x32 = picture.triangle2.right / y32 = picture.triangle2.bottom / a2 = ((expressions.y22  expressions.y32)*(mouse.x  expressions.x32) + (expressions.x32  expressions.x22)*(mouse.y  expressions.y32)) / ((expressions.y22  expressions.y32)*(expressions.x12  expressions.x32)+(expressions.x32  expressions.x22)*(expressions.y12  expressions.y32)) / b2 = ((expressions.y32  expressions.y12)*(mouse.x  expressions.x32) + (expressions.x12  expressions.x32)*(mouse.y  expressions.y32)) / ((expressions.y22  expressions.y32)*(expressions.x12  expressions.x32)+(expressions.x32  expressions.x22)*(expressions.y12  expressions.y32)) / c2 = 1  expressions.a2  expressions.b2 </expressions> <text report> / items = ("<%mouse.x%>, <%mouse.y%>, <%expressions.a%>, <%expressions.b%>, <%expressions.c%>", <%expressions.a2%>, <%expressions.b2%>, <%expressions.c2%> / position = (50, 15) </text> <trial mytrial> / stimulusframes = [1 = triangle1, triangle2, report] / validresponse = (picture.triangle1, picture.triangle2) / inputdevice = mouse / isvalidresponse = [ 0<=expressions.a && expressions.a <= 1 && 0 <= expressions.b && expressions.b <= 1 && 0 <= expressions.c && expressions.c <= 1  0<=expressions.a2 && expressions.a2 <= 1 && 0 <= expressions.b2 && expressions.b2 <= 1 && 0 <= expressions.c2 && expressions.c2 <= 1 ] </trial> <block myblock> / trials = [13 = mytrial] </block> Yellow triangle is practice_triangle1.png and green is practice_triangle2.png At the moment, as I understand it, the  condition in the / isvalidresponse is making the triangle test effectively useless, and I can click on either 'triangle' but the response registered is the first image. Does anyone have any ideas to tie the mouse location to a specific triangle, even though they overlap? Cheers, Morgan You'll want to do something like this: <picture triangle1> / items = ("practice_triangle1.png") / position = (50,50) </picture> <picture triangle2> / items = ("practice_triangle2.png") / position = (50,50) </picture> <expressions triangle1> / x1 = picture.triangle1.left / y1 = picture.triangle1.bottom / x2 = picture.triangle1.left / y2 = picture.triangle1.top / x3 = picture.triangle1.right / y3 = picture.triangle1.bottom / a = ((expressions.y2  expressions.y3)*(mouse.x  expressions.x3) + (expressions.x3  expressions.x2)*(mouse.y  expressions.y3)) / ((expressions.y2  expressions.y3)*(expressions.x1  expressions.x3)+(expressions.x3  expressions.x2)*(expressions.y1  expressions.y3)) / b = ((expressions.y3  expressions.y1)*(mouse.x  expressions.x3) + (expressions.x1  expressions.x3)*(mouse.y  expressions.y3)) / ((expressions.y2  expressions.y3)*(expressions.x1  expressions.x3)+(expressions.x3  expressions.x2)*(expressions.y1  expressions.y3)) / c = 1  expressions.a  expressions.b </expressions> <expressions triangle2> / x12 = picture.triangle2.left / y12 = picture.triangle2.top / x22 = picture.triangle2.right / y22 = picture.triangle2.top / x32 = picture.triangle2.right / y32 = picture.triangle2.bottom / a2 = ((expressions.y22  expressions.y32)*(mouse.x  expressions.x32) + (expressions.x32  expressions.x22)*(mouse.y  expressions.y32)) / ((expressions.y22  expressions.y32)*(expressions.x12  expressions.x32)+(expressions.x32  expressions.x22)*(expressions.y12  expressions.y32)) / b2 = ((expressions.y32  expressions.y12)*(mouse.x  expressions.x32) + (expressions.x12  expressions.x32)*(mouse.y  expressions.y32)) / ((expressions.y22  expressions.y32)*(expressions.x12  expressions.x32)+(expressions.x32  expressions.x22)*(expressions.y12  expressions.y32)) / c2 = 1  expressions.a2  expressions.b2 </expressions> <text report> / items = ("<%mouse.x%>, <%mouse.y%>, <%expressions.a%>, <%expressions.b%>, <%expressions.c%>, <%expressions.a2%>, <%expressions.b2%>, <%expressions.c2%>") / position = (50, 15) </text> <trial mytrial> / ontrialbegin = [ values.response = ""; ] / stimulusframes = [1 = triangle1, triangle2, report] / validresponse = (lbuttondown) / inputdevice = mouse / isvalidresponse = [ if(0<=expressions.a && expressions.a <= 1 && 0 <= expressions.b && expressions.b <= 1 && 0 <= expressions.c && expressions.c <= 1){ values.response = "triangle1"; true; } else if(0<=expressions.a2 && expressions.a2 <= 1 && 0 <= expressions.b2 && expressions.b2 <= 1 && 0 <= expressions.c2 && expressions.c2 <= 1){ values.response = "triangle2"; true; } ] </trial> <block myblock> / trials = [13 = mytrial] </block> <values> / response = "" </values> <data> / columns = (date time subject group blocknum blockcode trialnum trialcode values.response latency) / separatefiles = true </data> Legend!


